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  Calculating % Arenosa
How do I determine % of Arenosa breeding for my horse?


This question comes up from time to time.  I've also seen horses advertised as a certain % Arenosa and, when I do my own research, I find that the % is not accurate. I do not believe the owner is trying to deceive anyone.  I think there is just a lot of mid-understanding about what it means to be X% Arenosa, and about genetics in general.  Since most of our horses have Arenosa breeding, I thought I'd try to explain how the % of Arenosa breeding is calculated.

I will apologize up front that the explanation seems so long, and some of you may want to skip down to Examples 2 and 3.  I am happy to help anyone determine what % of Arenosa their horse is.


Contents:
A.  Important Background Information
     1.  What is an a Arenosa Horse or Pony?
     2.  About Heredity
          Example 1:  A Human Example
     3.  Common Mistakes
B.  Example 2:  Horse A - 50% Arenosa
C.  Example 3:  Offspring of Horses 1 & 2 will be 43.75% Arenosa


A. Important Background Information
First, some very important background information.  Don't skip this!

1.  What is an Arenosa Horse or Pony?
An Arenosa, "Arenosa-bred", or % Arenosa-bred horse is one that has one or more ancestors that were BRED (not just owned) by Audrey Barrett of Arenosa Pony Farm.  Most horses that were bred by Audrey Barrett have a name ending in "of Arenosa".  These horses are 100% Arenosa.

2.  About Heredity
A. A horse (or human) can only inherit genetic material through its parents.   If you have your "grandfather's eyes", it is because your parent inherited them first, then your parent passed them on to you.  You cannot inherit anything DIRECTLY from your grandparents.  If your grandparent has a trait, and that trait is not passed to your parent, it can never be passed to any of your parent's children.  All genetic contributions made by your grandparents are indirect, coming through your parents.  

B.  A horse (or human) inherits 50% - no more and no less - of its genetic material from each parent.

An example to apply the principles above:

Example 1:  A Human Example

Mother
(50% Welsh)
Grandfather
(100% Welsh)
Welsh (100%) Welsh (100%)
Welsh (100%)
Welsh (100%) Welsh (100%)
Welsh (100%)
Grandmother
(100% Dutch)
   
 
   
 

My maternal grandfather is 100% Welsh.  I can only inherit genetic material from my parents, so I have to figure out what % of Welsh my mother is.  She gets half (1/2) of her genetic make-up from her father, which makes her:

1/2 x 100% (from her father) = 50% Welsh

I get half of my genetic make-up from my mother.  This makes me:

1/2 x 50% (from my mother) = 25% Welsh

It doesn't matter that my grandfather's parents and grandparents were all 100% Welsh.  Their genetic contribution can ONLY be made through my mother.  My mother can only get 50% (no more and no less) of her genes from her father, and, since her mother was not Welsh, she cannot be more than 50% Welsh and I cannot be more than 1/2 x 50% = 25% Welsh - no matter how  many Welsh ancestors there are in her father's background.

3.  Common Mistakes
A. There is no "Arenosa" gene.  When we talk about genes/genetics in this article, we are really talking about how much of a horse's genetic make-up comes from horses that were bred by Audrey Barrett.  "Arenosa breeding" or "Arenosa influence" would probably be better terms.

B. The number of Arenosa Horses in a pedigree does not matter.  Only the % of genetic material/influence passed down.  A horse with 4 great-grandparents that were bred by Audrey Barrett is a SMALLER % Arenosa than a horse with 2 parents that were bred by Audrey Barrett.   The NUMBER of Arenosa ancestors doesn't matter.  It is the % of genetic material that has been passed down that matters. 

C. Not all "of Arenosa" horses were bred by Audrey Barrett.  While almost all horses whose registered names end in "of Arenosa" were bred by directly Audrey Barrett and therefore are 100% Arenosa, there is another farm that recently started using this name.  There are also rumors that Audrey Barrett may have allowed other farms to use "of Arenosa" in their horses' names.  It doesn't mean these horses are not Arenosa-bred, but you may need to do further research to determine if an "of Arenosa" horse was actually bred by Audrey Barrett and, if not, what % Arenosa that horse actually is.  

D. Horses with the name "Kewpie" may not be Arenosa-bred Horses. Another very common mistake is to assume horses with the name "Kewpie" are Arenosa horses.  While some "Kewpie" horses were OWNED by Audrey Barrett, they were not necessarily BRED by Audrey Barrett, and therefore are NOT Arenosa horses.


B.  Example 2:  Horse A - 50% Arenosa
Okay, let's look at some examples.  After a while, you'll be able to figure it out at a glance.  But at first, it is easiest to break it down.

Example 2:  Horse A - 50% Arenosa

Horse A Horse B
(Sire)
Horse D
Horse E
Horse C  of Arenosa
(Dam)
Horse F of Arenosa
Horse G of Arenosa

1. Horse A's Dam
We can see that the Horse C is an "of Arenosa" horse.  After verifying that Horse C was indeed BRED by Audrey Barrett, we conclude that Horse C is 100% Arenosa.

Remember:  Once you have identified a Horse as 100% Arenosa, IGNORE THAT HORSE'S ANCESTORS
(indicated by strike through).   Horses F & G can only contribute genetic material through Horse C, so once you  have determined the % Arenosa of Horse C, you are finished with Horse C's ancestors. (See About Heredity above)

2. Horse A's Sire
There are no "of Arenosa" horses in Horse B's pedigree.  Therefore Horse B contributes 0% Arenosa breeding to Horse A.

3.  Conclusion
Horse A
gets 1/2 of it's genetic material from Horse B and 1/2 from Horse C:
Horse B's
contribution: 1/2 x 0% = 0%
Horse C's
contribution: 1/2 x 100% = 50%
Horse A is 0% + 50% = 50% Arenosa
 

Horse A
50% Arenosa
Horse B  (Sire)
0% Arenosa
Horse C  of Arenosa (Dam)
100% Arenosa

 

 

C.  Example 3:  Offspring of Horses 1 & 2 - 43.75% Arenosa

Let's try a complicated pedigree.

Example 2:  Offspring of Horses 1 & 2 will be 43.75% Arenosa

Okay if that made you want to tear your hair out, try this one.  Remember:  Each horse gets 50% of its genetic material from its sire and 50% from its dam.

For this example, you want to determine what % Arenosa the offspring of Horse 1 and Horse 2 will be. 

1.  You research the pedigree of Horses 1 & 2 (below) and find that 8 horses were bred by Audrey Barrett:  Horse 9, 13, 17, 18, 19, 23, 27, 28.  Each of these horses is 100% Arenosa. 

Once you have identified a horse as 100% Arenosa, you do not need to consider any of that horse's ancestors.  (A line cannot contribute more than 100%!). (For more information on this principle, see Example 1 above).  Cross off all ancestors of 100% Arenosa horses.  This leaves you with five (5) 100% Arenosa Horses to consider:  9, 13, 17, 18, 23.

 
Parents or
Breeding Pair
Grand Parent's Great Grand Parents Great-Great Grand Parents
Horse 1
(Sire)
Horse 3 Horse 7 Horse 15
Horse 16
Horse 8 Horse 17 of Arenosa
Horse 18 of Arenosa
Horse 4 Horse 9 of Arenosa Horse 19 of Arenosa
Horse 20
Horse 10 Horse 21
Horse 22
Horse 2
(Dam)
Horse 5 Horse 11 Horse 23 of Arenosa
Horse 24
Horse 12 Horse 25
Horse 26
Horse 6 Horse 13 of Arenosa Horse 27 of Arenosa
Horse 28 of Arenosa
Horse 14 Horse 29
Horse 30

2.  Next, start with earliest generation where there are 100% Arenosa horses that are not crossed off and figure out the % of Arenosa of each of their OFFSPRING.  The earliest 100% Arenosa horses are among the Great-Great Grand Parents in this example, so we will start by figuring out the % Arenosa of each of the Great Grand Parents.

Horse % Arenosa How % was Computed
7 0% No Arenosa-bred ancestors
8 100% Both of Horse 8's parents are 100% Arenosa, and therefore Horse 8 is 100% Arenosa, even though it was not bred by Audrey Barrett:

1/2 x 100% (from Horse 17)= 50%
1/2 x 100% (from Horse 18) = 50%
50% + 50% = 100%
9 100% Horse 9 was bred by Audrey Barrett, and therefore is 100% Arenosa
10 0% No Arenosa-bred ancestors
11 50% Has one parent that is 100% Arenosa (horse 23).  Horse 8 gets half of its genetic makeup from each parent and therefore is 1/2 x 100% = 50% Arenosa
12 0% No Arenosa-bred ancestors
13 100% Horse 13 was bred by Audrey Barrett, and therefore is 100% Arenosa
14 0% No Arenosa-bred ancestors

We are finished with the Great-Great Grandparents, so the pedigree now looks like this:

Parents or
Breeding Pair
Grand Parent's Great Grand Parents
Horse 1
(Sire)
Horse 3 Horse 7
0%
Horse 8
100%
Horse 4 Horse 9 of Arenosa
100%
Horse 10
0%
Horse 2
(Dam)
Horse 5 Horse 11
50%
Horse 12
0%
Horse 6 Horse 13 of Arenosa
100%
Horse 14
0%

3.  Now figure out the next generation - the Grand Parents:

Horse % Arenosa How % was Computed
3 50% Horse 3's Sire has no Arenosa breeding
Horse 3 gets half its genetic make-up from its dam, Horse 8:   1/2 x 100% = 50%
4 50% Horse 4's dam has no Arenosa breeding
Horse 4 gets half of its genetic make-up from its sire, Horse 9: 1/2 x 100% = 50%
5 25% Horse 5's dam has no Arenosa breeding
Horse 3 gets half it's genetic make-up from its sire, Horse 11: 1/2 x 50% = 25%
6 50% Horse 6's dam has no Arenosa breeding
Horse 6 gets half of its genetic make-up from its sire, Horse 13: 1/2 x 100% = 50%

We are finished with the Great-Great Grandparents, so the pedigree now looks like this:

Parents or
Breeding Pair
Grand Parent's
Horse 1
(Sire)
Horse 3
50%
Horse 4
50%
Horse 2
(Dam)
Horse 5
25%
Horse 6
50%

4.  Now figure out what % Arenosa each parent is:

Horse % Arenosa How % was Computed
1 50% Horse 3, contributes half of Horse 1's genetic make-up:
1/2 x 50% = 25%
Horse 4 contributes the other half of Horse 1's genetic make-up:  1/2 x 50% = 25%

25% (from Horse 3) + 25% (from Horse 4) = 50%
2 37.5% Horse 5, contributes half of Horse 2's genetic make-up:
1/2 x 25% = 12.5%
Horse 6 contributes the other half of Horse 2's genetic make-up:  1/2 x 50% = 25%

12.5% (from Horse 5) + 25% (from Horse 6) = 37.5%

4. Finally, determine what % Arenosa the offspring of Horse 1 and Horse 2 will be:
Horse 1 contributes half of the genetic material:

1/2 x 50% = 25%

Horse 2 contributes the other half of the genetic material:

1/2 x 37.5% =  18.75%

Offspring of Horse 1 & 2 will be:  25% + 18.75% = 43.75% Arenosa

In case you are interested, here are the percentages of all of the horses in pedigrees for Horses 1 & 2:

Parents or
Breeding Pair
Grand Parent's Great Grand Parents Great-Great Grand Parents
Horse 1
(Sire)
50%
Horse 3
50%
Horse 7
0%
Horse 15
0%
Horse 16
0%
Horse 8
100%
Horse 17 of Arenosa
100%
Horse 18 of Arenosa
100%
Horse 4
50%
Horse 9 of Arenosa
100%
Horse 19 of Arenosa
100%
Horse 20
0%
Horse 10
0%
Horse 21
0%
Horse 22
0%
Horse 2
(Dam)
37.5%
Horse 5
25%
Horse 11
50%
Horse 23 of Arenosa
100%
Horse 24
0%
Horse 12
0%
Horse 25
0%
Horse 26
0%
Horse 6
50%
Horse 13 of Arenosa
100%
Horse 27 of Arenosa
100%
Horse 28 of Arenosa
100%
Horse 14
0%
Horse 29
0%
Horse 30
0%

 

If you compare Examples 2 and 3, you will notice that Example 2 has only 1 Arenosa ancestor, and yet has a higher % of Arenosa breeding than Example 3, which has 8 Arenosa ancestors!

Again, I'm happy to help anyone figure out the % of Arenosa breeding of their horses.  But for those of you who prefer to do it yourself, I hope this has been helpful.

 



Alpha Farm ~ Ronaele Carpenter ~ Lebanon, Ohio
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